Step 6 - you're not allowed to divide by 0 (= a + b - c - d)
2006-12-09 01:49:53
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answer #1
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answered by Anonymous
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The mistake is that if we assume that a + b = c + d, then in Step 5, (a + b - c - d) is equal to 0 since (a +b - c - d) = (a + b) - (c + d).
This means that in Step 6, you are dividing both sides of the equation by 0 which is not allowed. This is the Step where the actual mistake is made.
2006-12-09 09:53:28
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answer #2
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answered by math_guy112358 1
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Actually the equation reaches a conclusion at step 5:
Step 5......3 (a + b - c - d) = -1 (a + b - c - d)
3[(a+b)-(c+d)] = -1 [(a+b)-(c+d)]
3* 0 = -1*0
0 = 0
Which is correct.
So, as others have also put it, Step 6 is not allowed. What you are effectively doing is:
3[(a+b)-(c+d)] = -1 [(a+b)-(c+d)]
3 = -1 {[(a+b)-(c+d)] / [(a+b)-(c+d)] }
3 = -1 { 0/0}
Which leads to the erroneous results
2006-12-09 10:02:20
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answer #3
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answered by Professor Khanna 2
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step 5 leading to step 6 bring wrong because u divided by 0
2006-12-09 10:15:35
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answer #4
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answered by birdman 1
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step 5 ==>6
"Step 5......3 (a + b - c - d) = -1 (a + b - c - d)
Step 6.
.....(a + b - c - d)
.... ---------------- = -3 "
... (a + b - c -d)
3(a + b - c - d) + 1(a + b - c - d) = 0
2006-12-09 09:53:33
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answer #5
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answered by Anonymous
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step 6, since you cannot divide by 0 .
2006-12-09 20:50:35
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answer #6
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answered by Anonymous
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there are a lot of mistakes. why does step 2 have a 4, and step 3 goes to 3a. when you multiply 4(a+b) it equals 4a+4b.
2006-12-09 09:52:14
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answer #7
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answered by whiteafrican01 3
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Step 5:
3(a+b-c-d)= -1(a+b-c-d)
Step6:
3(a+b-c-d)/(a+b-c-d) = -1
Step7:
(a+b-c-d)/(a+b-c-d) = -1/ 3
Step8:
1=-1/ 3
Step 9: 3= -1 or -3 = 1
2006-12-09 10:08:57
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answer #8
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answered by Anonymous
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step 6 is the mistake,
you divide by 0= a + b - c -d
which is a no-no.....
2006-12-09 09:51:25
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answer #9
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answered by locuaz 7
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(a + b - c -d) equals zero. Division by zero in step 6 is undefined.
2006-12-09 09:55:15
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answer #10
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answered by Jerry P 6
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