In the standard (x,y) coordinate plane, the graph of?

Question

(x - 2)2 + (y + 4)2 = 9 is a circle.
What is the area enclosed by this circle, expressed in square coordinate units?

Answer 1

The equation (x-h)²+(y-k)² = r² describes a circle of radius r centered at the coordinates (h,k) so the circle you have is centered at (2, -4) and has a radius of 3. And, like all circles, the area is given by A = πr² so your circle has an area of 9π = 28.274.

Hope that helps.


Doug

Answer 2

the equation:
(x - 2)^2 + (y + 4)^2 = 9
describes a circles of radius r=3,
[centered in Xc=2, Yc=-4]
so the area is pi*r^2=3.14*9=28.26

remember that the circle equation is:
(x -Xc)^2+(y+Yc)^2=r^2

Answer 3

assume you mean squared by the (x-2)2.

circle has radius sqrt(9)=3

Area =9*pi

Answer 4

(pie)Rsquared!!!