find f o g if f(x) = ln x and g (x) = x^2-9?

Answer 1

(f o g)(x) or 'f composite g' is defined as f(g(x)). This means, for every 'x' in f(x), put in g(x). This means that:

'f composite g' = f(x^2+9). Now we place this into f, thus:

'f composite g' = ln(x^2+9)

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Hope this helps

Answer 2

Your first step is stating what (f o g)(x) means, so that's what we do.

(f o g)(x) is defined to be f(g(x)). Plugging in g(x) for the inside of the function f, we get

f(g(x)) = f (x^2 - 9)

And now, plugging in x^2 - 9 for every instance of x in the function of f, we get

ln(x^2 - 9)

That's our answer. (f o g) (x) = ln(x^2 - 9).

If you wanted to get technical, you can actually change the form of that.

ln(x^2 - 9) = ln ( [x-3][x+3] ) = ln (x-3) + ln (x+3)

Answer 3

basically f o g = f[g(x)] = ln [x^2 - 9]

Answer 4

basically it looks like

ln (x^2 - 9)

there you go

Answer 5

simple :


ln (x^2 - 9) for sure

Answer 6

fog => f [g(x)] => f [ x^2.9] => ln(x^2.9)