Two bowling bowls each have a mass of 6.8 kg. They are located next to each other with their centers 21.8...?

Question

Two bowling bowls each have a mass of 6.8 kg. They are located next to each other with their centers 21.8 cm apart. What gravitational force do they exert on each other.

Please help me understand this problem.
I'm having trouble understanding it.

Answer 1

For this you must use the formula:

F = (GMm)/(R)^2
Where F is the Gravitational force
G is the Gravitational Constant = 6.67*10^(-11)
M is the mass of the heavier object
m is the mass of the lighter object
and R is the distance between the centre of mass.

Solve:
21.8 cm = 0.218 m
F = (GMm)/(R)^2
= {6.67*10^(-11) * 6.8 * 6.8}/(0.218)^2
= 0.000000003084208 /0.047524
= 6.4897904216816766265465869876273 Newtons
= 6.5 N (approx)