P = purple, pp = white. The offspring of a cross between two heterozygous purple-flowering plants (Pp × Pp) r

Question

P = purple, pp = white. The offspring of a cross between two heterozygous purple-flowering plants (Pp × Pp) results in


a. all purple-flowered plants.

b. purple-flowered plants and white-flowered plants.

c. two types of white-flowered plants: PP and Pp.

d. all white-flowered plants.

e. all pink-flowered plants.

Answer 1

If we set up a punnet square, then we get:

___P__p
P PP Pp
p Pp pp

PP and Pp are purple flowered plants
pp is a white flowered plant

So we know it can't be a because we have white plants. B seems to work at this point. C can't be right because we know PP and Pp produce purple plants. Looking at D and E, we know they are wrong because we have purple flowers and no pink flowers. So the answers is . . .

Answer 2

Do you know how a Punnett square works? Look in your textbook.

P p
-----------------------
P | PP Pp
|
p | Pp pp

Resulting in a 25% chance of white-flowered plants and a 75% chance of purple ones. Therefore the answer is b. It can't be c. because a capital P means purple, so PP can't be a white-flowered plant.

Answer 3

Pardon my terminology, but look at your text book, dumbo. Think about it. If you have the question to list out in so specific of a form, it must have come from a text. The text will not require you to give an answer which they have not equipped you to do. Now in a Pp*Pp cross you can get_______

PP, Pp, Pp, and pp

Simple Punett square

Sorry for being so mean.

Answer 4

b.

PP = purple
Pp = purple
pP = purple
pp = white

Purple : white 3:1

Answer 5

PP, Pp, Pp, pp. That would be b, c.