How do I calculate terminal velocity?

Answer 1

It's not a fun equation but here it is...

Mathematically, terminal velocity is described by the equation

V= sqrt(2mg)/(ρ A Cd))

where

V is the terminal velocity,
m is the mass of the falling object,
g is gravitational acceleration,
Cd is the drag coefficient,
ρ is the density of the fluid the object is falling through, and
A is the object's cross-sectional area.

Answer 2

That is a very very complicated thing to calculate. When the drag of the medium equals the force of gravity, you have reached terminal velocity. Calculating the drag is not an exact science but here's a good reference.

http://en.wikipedia.org/wiki/Drag_(physics)

Answer 3

Hi. You need to consider two opposing forces, gravity and air resistance. Gravity initially accelerates an object at 9.8m per second per second. Air resistance climbs from zero until it balances the gravity force. I do not know the formula, sorry, but in a human being in a stable arch position the end velocity is about 128 or so MPH.

Answer 4

Velocity(terminal) = SQRT( (2W)/(Cd p A))

where
W = weight
Cd = Coefficient of drag
p = gas density
A = frontal area

Answer 5

The formula for it is:

V(term) = sqrt[2mg/(p*A*C(drag))]

where m is the mass of the falling object
g = gravitational acceleration
p = air density (or density of other medium)
A = cross-sectional area of falling mass
C(drag) = Drag co-efficient of air (or of other medium)

Here's a link:

http://en.wikipedia.org/wiki/Terminal_velocity

Answer 6

You would also need the cross-sectional area of the object falling, as well as the drag coefficient. See below for the formula.

Answer 7

Vterminal= √{2W / (Cd*p*A)}
w=weigh
Cd= drag coefficient
p= air density
A= Frontier area.