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Q is a Hermitian matrix, S is an arbitrary subspace of R^J.

2006-12-08 11:36:56 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

Q Hermitian: Q=Q*

First ->
Say QS = S

For v e S and w e S^perp

Qv e S

= 0 = =

Therefore Qw is orthog to v and hence Qw e S^perp

<-
QS^perp = S^perp

(same idea)

for v e S^perp , Qv e S^perp
w e S

= 0 = =
therefore Qw e S

2006-12-08 13:04:59 · answer #1 · answered by modulo_function 7 · 0 0

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