mass of the cylinder
2006-12-08 11:13:38 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Volume of a cylinder: pi*r*r*t (pi = 22/7 or 3.14, i use 22/7 for its accuracy)
Volume = (22/7) * 5 * 5 * 15 = 1178.57cm^3
Mass = density * volume
Mass = 6g/cm^3 * 1178.57cm^3 = 7071.43 g
2006-12-08 11:15:59 · answer #1 · answered by Xiangwei Xi 3 · 0⤊ 0⤋
First calculate the volume of the cylinder.
V = pi r^2 h = pi*(5^2)*15 = pi*25*15 = 375pi cc
Mass = Volume*Density = 375pi*6 = 2250pi = 7068.58 gm
2006-12-08 11:20:05 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
Volume = pi x r^2 x h
= 3.14 x 25 x 15
= 350 x 3.14
= 1177.5 cm^3
Density = Mass/Volume
therefore mass = Density x volume
= 6 x 1177.5
= 7065 g
= 7.065 Kg
2006-12-08 11:19:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
volume of cylinder is pi *radius squared*height
3.14*5*5*15=1177.5
Density = mass/volume
6g/cm=mass/1177.5cm = 7065g
2006-12-08 11:30:02 · answer #4 · answered by Anonymous · 0⤊ 0⤋
V=πr^2h=π*5^2*15=375π=1178.0972450961724644234912687
m=V*rho=1178.0972450961724644234912687298*6
m=7068.58g or 7.06858kg
2006-12-08 13:55:12 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋