Two tricky problems?

Question

Give the asymptote of the function

g(x)= 4 to the (x+5) -7

and

find the range of the function

g(x)= -2 to the (x) +4

Answer 1

g(x) = 4^(x + 5) - 7

Since there is no restriction in the domain of the function, then there is no vertical asymptote. To get the horizontal asymptote, get the limit of the function as x approaches both infinities. If the limit is n, then the line y = n is a horizontal asymptote. Thus,
lim x-->∞ g(x) = ∞, but
lim x-->-∞ g(x) = -7,
so the line y = -7 is a horizontal asymptote of the function.

____________
g(x) = -2^x + 4

We know that this is an exponential curve going downward, so the range is from -∞ to a certain number, which, in this case, the limit at -∞. Thus,
lim x-->-∞ g(x) = 4,
so the range is from -∞ to 4 exclusive, or (-∞,4)

^_^

Answer 2

I would answer it, but something is wrong with the description to the question, are you saying G(x)= (x+5) -7, I am not understanding

Answer 3

g(x)= 4^(x+5) -7

asymptote is -7

g(x)= (-2)^x +4

-∞ < g(x) < ∞

Answer 4

go to hotmath.com and get the answer to the question

Answer 5

you need to fine what x = to then go from there

Answer 6

do your own homework