2006-12-08 08:54:13 · 4 answers · asked by Amanda Skrivanek 1 in Science & Mathematics ➔ Chemistry
See the following links for detailed explanations.
http://www.mpcfaculty.net/mark_bishop/Redox_balancing.htm
http://www.science.uwaterloo.ca/~cchieh/cact/c123/balance.html
http://www.physchem.co.za/Redox/Balance.htm
http://home.c2i.net/astandne/help_htm/english/problems/redox-electrochemistry.htm
http://chemistry.about.com/od/generalchemistry/ss/redoxbal.htm
2006-12-08 10:12:55 · answer #1 · answered by rm 3 · 0⤊ 0⤋
The total upward oxidation number change must equal the total downward oxidation number change. Another way of putting this is that the total number of electrons gained by the oxidising agent must equal the total number given away by the reducing agent.
You have to adjust the balancing numbers of each half equation until this is so.
2006-12-08 09:49:04 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋
letter c is your superb answer because of the fact the different techniques are examples of a double displacement reaction....and in case you notice heavily, the copper oxide is being decreased or oxidized to copper with carbon dioxide being released. wish that helps!
2016-12-11 05:08:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋
it depends on the oxidation-reduction equation you are given.
2006-12-08 09:00:47 · answer #4 · answered by soilikepink 1 · 0⤊ 0⤋