36 quarters and rest nickels.
Assume all the coins are nickels
If that is so, the total value of coins would be 0.05x79=3.95.
For every nickel we change to quarter, the total value will increase by 0.20.
11.15-3.95=7.20
7.20/0.20=36 quarters.
Hence, the answer is 36 quarters and 43 nickels.
2006-12-08 07:50:34
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answer #1
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answered by Anonymous
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One of the things you can do to know if you answered right is to actually gather that many quarters and nickels. :)
But foolings aside, sure I can help.
There are 79 coins consisting of quarters and nickels. I'm going to let
Q = number of quarters
N = number of nickels.
That means
Q + N = 79
All the coins equal 11.15. That means
0.25Q + 0.05 N = 11.15
That makes this a system of equations
Q + N = 79
0.25Q + 0.05N = 11.15
Since we're really only interested in how many nickels there are, we should use substitution. Since Q + N = 79, then Q = 79 - N
So we plug Q = 79 - N into the second equation and solve for N.
0.25(79 - N) + 0.05N = 11.15
19.75 - (0.25)N + 0.05N = 11.15
19.75 - (0.20)N = 11.15
-(0.20)N = -8.6
N = 43
There are 43 nickels.
To get the number of quarters, we use Q = 79 - N = 79 - 43 = 36.
Don't believe me that these add up to $11.15? Let's check.
36 quarters; every 4 quarters make a dollar. So this is $9.00
43 nickels; every 20 nickels make a dollar. so this is $2.00 plus 15 cents remaining, or $2.15
$9.00 + $2.15 = $11.15
2006-12-08 07:56:17
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answer #2
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answered by Puggy 7
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Let x be the number of nickels and y the number of quarters.
Then x + y = 79.
Now write the equation for the value of the coins in pennies.
Total value of nickels = 5x
Total value of quarters = 25y
so 5x + 25y = 1115.
Dividing by 5 gives us
x + 5y = 223.
Subtracting the first equation from the second gives
4y = 144
y = 36 quarters.
x = 79 - 36 = 43 nickels.
Check: 43*5 + 36*25 = 1115.
This is a nice example of what I like to call
a value problem. They are all basically
solved like this one.
Did you get it? I hope so. If not, sit down and have
a nice cry!
2006-12-08 08:38:55
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answer #3
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answered by steiner1745 7
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To make 79 coins quarters and nickles you would need 36 Quarters and 43 Nickles which sums to $11.15
2006-12-08 07:54:46
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answer #4
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answered by JimE 2
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If the question is phrased "what 2 funds can equivalent 30 cents. One isn't a nickle" then the respond is 1 / 4 and a nickle because of fact 1 / 4 isn't a nickle and in straightforward terms one does not might desire to be a nickle
2016-10-14 07:06:15
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answer #5
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answered by trinkle 4
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So you have Q quarters and N nickels.
Q + N = 79 (total number of coins), which means N = 79 - Q
(.25)(Q) + (.05)(N) = 11.15
Substituting for N,
(.25)(Q) + (.05)(79-Q) = 11.15
.25Q +(.05*79) -.05Q = 11.15
.25Q -.05Q + 3.95 = 11.15
.20Q = 7.20
Q = 36
so N = 79-36 = 43
Check:
.25 * 36 + .05 * 43 = 9 + 2.15 = 11.15
2006-12-08 08:07:51
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answer #6
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answered by Grizzly B 3
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Let X = #Quarters; Y=#Nickles.
(1) X+Y=79
(2) .25X +.05Y =11.5
Solve the above equations and get:
X = 36
Y = 43
Answer: There are 43 Nickles.
2006-12-08 08:02:12
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answer #7
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answered by lm 3
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43nickles =$2.15 36 quarters=$9.00 79 coins = $11.15 GOOD LUCK!
2006-12-08 08:07:42
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answer #8
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answered by Anonymous
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Q * 0.25 + N * 0.05 = 11.15
Q + N =79
Two equations in two variables is easily solved.
Q = 79 - N
SO...
(79 - N) * 0.25 + N * 0.05 = 11.15
Plug and chug...solve for N
Then plug N into Q= 79 - N to get Q.
Done!
2006-12-08 08:49:32
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answer #9
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answered by Jerry P 6
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43 nickles = $2.15
36 quarters=$ 9.00
$11.15
2006-12-08 07:51:52
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answer #10
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answered by law-inspired 3
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