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How many Nickles are there?...

Please someone I need desperate help in this one I just want to know if I answered right.

2006-12-08 07:48:06 · 14 answers · asked by icechampagne81 2 in Science & Mathematics Mathematics

14 answers

36 quarters and rest nickels.

Assume all the coins are nickels
If that is so, the total value of coins would be 0.05x79=3.95.

For every nickel we change to quarter, the total value will increase by 0.20.

11.15-3.95=7.20
7.20/0.20=36 quarters.

Hence, the answer is 36 quarters and 43 nickels.

2006-12-08 07:50:34 · answer #1 · answered by Anonymous · 1 1

One of the things you can do to know if you answered right is to actually gather that many quarters and nickels. :)

But foolings aside, sure I can help.

There are 79 coins consisting of quarters and nickels. I'm going to let

Q = number of quarters
N = number of nickels.

That means

Q + N = 79

All the coins equal 11.15. That means

0.25Q + 0.05 N = 11.15

That makes this a system of equations

Q + N = 79
0.25Q + 0.05N = 11.15

Since we're really only interested in how many nickels there are, we should use substitution. Since Q + N = 79, then Q = 79 - N

So we plug Q = 79 - N into the second equation and solve for N.

0.25(79 - N) + 0.05N = 11.15
19.75 - (0.25)N + 0.05N = 11.15
19.75 - (0.20)N = 11.15
-(0.20)N = -8.6
N = 43

There are 43 nickels.

To get the number of quarters, we use Q = 79 - N = 79 - 43 = 36.

Don't believe me that these add up to $11.15? Let's check.

36 quarters; every 4 quarters make a dollar. So this is $9.00
43 nickels; every 20 nickels make a dollar. so this is $2.00 plus 15 cents remaining, or $2.15

$9.00 + $2.15 = $11.15

2006-12-08 07:56:17 · answer #2 · answered by Puggy 7 · 0 0

Let x be the number of nickels and y the number of quarters.
Then x + y = 79.
Now write the equation for the value of the coins in pennies.
Total value of nickels = 5x
Total value of quarters = 25y
so 5x + 25y = 1115.
Dividing by 5 gives us
x + 5y = 223.
Subtracting the first equation from the second gives
4y = 144
y = 36 quarters.
x = 79 - 36 = 43 nickels.
Check: 43*5 + 36*25 = 1115.
This is a nice example of what I like to call
a value problem. They are all basically
solved like this one.
Did you get it? I hope so. If not, sit down and have
a nice cry!

2006-12-08 08:38:55 · answer #3 · answered by steiner1745 7 · 0 0

To make 79 coins quarters and nickles you would need 36 Quarters and 43 Nickles which sums to $11.15

2006-12-08 07:54:46 · answer #4 · answered by JimE 2 · 0 1

If the question is phrased "what 2 funds can equivalent 30 cents. One isn't a nickle" then the respond is 1 / 4 and a nickle because of fact 1 / 4 isn't a nickle and in straightforward terms one does not might desire to be a nickle

2016-10-14 07:06:15 · answer #5 · answered by trinkle 4 · 0 0

So you have Q quarters and N nickels.
Q + N = 79 (total number of coins), which means N = 79 - Q
(.25)(Q) + (.05)(N) = 11.15
Substituting for N,
(.25)(Q) + (.05)(79-Q) = 11.15
.25Q +(.05*79) -.05Q = 11.15
.25Q -.05Q + 3.95 = 11.15
.20Q = 7.20
Q = 36
so N = 79-36 = 43

Check:
.25 * 36 + .05 * 43 = 9 + 2.15 = 11.15

2006-12-08 08:07:51 · answer #6 · answered by Grizzly B 3 · 0 0

Let X = #Quarters; Y=#Nickles.
(1) X+Y=79
(2) .25X +.05Y =11.5

Solve the above equations and get:
X = 36
Y = 43

Answer: There are 43 Nickles.

2006-12-08 08:02:12 · answer #7 · answered by lm 3 · 0 0

43nickles =$2.15 36 quarters=$9.00 79 coins = $11.15 GOOD LUCK!

2006-12-08 08:07:42 · answer #8 · answered by Anonymous · 0 0

Q * 0.25 + N * 0.05 = 11.15

Q + N =79

Two equations in two variables is easily solved.

Q = 79 - N

SO...

(79 - N) * 0.25 + N * 0.05 = 11.15

Plug and chug...solve for N

Then plug N into Q= 79 - N to get Q.

Done!

2006-12-08 08:49:32 · answer #9 · answered by Jerry P 6 · 0 0

43 nickles = $2.15
36 quarters=$ 9.00
$11.15

2006-12-08 07:51:52 · answer #10 · answered by law-inspired 3 · 0 1

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