2006-12-08 06:29:34 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
It's all about minimizing the energy level of the atom. Here, the energy cost of joining a shell already nearly full of like-charged particles is higher than the energy cost of just taking an orbit with a higher quantum number.
2006-12-08 13:25:52 · answer #1 · answered by Frank N 7 · 0⤊ 0⤋
as quickly as u hit the fourth potential ranges the 'D' block starts to fill. This block is the transition metals...the sequence that those components persist with is 4s1, 4s2, 3p1, 3p2, 3p3, 3p4, 3p4, 3p5,3p6,3p7,3p8, 3p9, 3p10, 4d1, 4d2, and so on and so on... as quickly as u get to the 6th potential point the f block starts to fill commencing with 6s's then 5d's then 6p's then the 4 f's, yet u shouldnt complication approximately that, in case you may then u r in chem in college and properly you may comprehend this...
2016-12-13 05:19:38 · answer #2 · answered by Anonymous · 0⤊ 0⤋