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It was a question asked by someone..
http://answers.yahoo.com/question/index?qid=20061207182048AAD7xgM&r=w#EsInW2DoADM76ecn4xv6qjRZ3zbwRe75iN1Gr0sylvXq6WFPBLPG

and, most people got "1" as the last digit for the answer.

but i never figured out, how even that's possible?

2006-12-08 04:43:15 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

umm, is there any reason, why three people come up with same answer?

2006-12-08 04:48:29 · update #1

thanks, yea.. i almost missed that thing!!!
and, fudged about that ...

2006-12-08 04:53:23 · update #2

11 answers

It's not an odd number.


The last digit will continue to go in a 4, 2, 6, 8, 4 pattern.

Maybe they tried to do it on a calculator. The number is far too large to be read on a calculator without scientific notation, thus some of the numbers are cut off.


edit: it is your mistake here. Their question was 19^598, which is not the same as 598^19 ;)

2006-12-08 04:48:58 · answer #1 · answered by Anonymous · 0 0

598^19 =
598 x 598 x 598 x 598 x 598 x 598 x
598 x 598 x 598 x 598 x 598 x 598 x
598 x 598 x 598 x 598 x 598 x 598 x 598

Now group up fot 598 x 598 x 598 = 213847192

213847192 x 213847192 x
213847192 x 213847192 x
213847192 x 213847192 x 598

now see 2 x 2 x 2 x 2 x 2 x 2 x 8 = even number

The anwer that you linked to has a typo, they found that:

598 x 598 x 598 = 213847129 instead of 213847192

2006-12-08 13:03:32 · answer #2 · answered by n_m_young 4 · 0 0

The original question asked for 19^598, not 598^19. It's just that some of the answerers started started answering 598^19. It is indeed true that 19^598 has 1 as its last digit. Cheers!

As a note, it goes to show how important it is for answerers to thoroughly read the question and all references provided ;)

2006-12-08 12:52:42 · answer #3 · answered by bag o' hot air 2 · 1 0

It is not possible.

598^19 = (2*249)^19= 2 * [(2^18) * (249^19)]

2 times ANY integer is an even integer, by definition, since even numbers are divisible by 2.

Done.

However, 19^598 is odd, since 19 is odd, and odds multiplied by odds are likewise always odd. Remember that an odd number cannot contain a factor of 2. Thus no number of odds multiplied by one another can ever have a factor of two, and so, cannot be even.

2006-12-08 12:52:12 · answer #4 · answered by Jerry P 6 · 0 0

since 598 is an even number 598^19 is an even number. Not an odd number

2006-12-08 12:51:38 · answer #5 · answered by ATS 2 · 0 0

The question asked "What is 19 to the power 598?" which means 19^598 (not 598^19).

598^19 is, of course, even.

2006-12-08 17:22:19 · answer #6 · answered by Anonymous · 0 0

It's an even number. If I multiply 598 or any
even number by itself any number of times
I still get an even number!

2006-12-08 14:26:13 · answer #7 · answered by steiner1745 7 · 0 0

298^19 (read as "298 to the power of 19") is an even integer, but
19^298 (read as "19 to the power of 298") is an odd integer.

I think you misinterpret the wording of the problem.

^_^

2006-12-08 21:45:49 · answer #8 · answered by kevin! 5 · 0 0

An even number times any number is always even. An even number raised to any power is even.

2006-12-08 12:45:51 · answer #9 · answered by Barkley Hound 7 · 0 0

it is an even number

2006-12-08 12:46:58 · answer #10 · answered by raj 7 · 0 0

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