It was a question asked by someone..
http://answers.yahoo.com/question/index?qid=20061207182048AAD7xgM&r=w#EsInW2DoADM76ecn4xv6qjRZ3zbwRe75iN1Gr0sylvXq6WFPBLPG
and, most people got "1" as the last digit for the answer.
but i never figured out, how even that's possible?
2006-12-08
04:43:15
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11 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Mathematics
umm, is there any reason, why three people come up with same answer?
2006-12-08
04:48:29 ·
update #1
thanks, yea.. i almost missed that thing!!!
and, fudged about that ...
2006-12-08
04:53:23 ·
update #2
It's not an odd number.
The last digit will continue to go in a 4, 2, 6, 8, 4 pattern.
Maybe they tried to do it on a calculator. The number is far too large to be read on a calculator without scientific notation, thus some of the numbers are cut off.
edit: it is your mistake here. Their question was 19^598, which is not the same as 598^19 ;)
2006-12-08 04:48:58
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answer #1
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answered by Anonymous
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598^19 =
598 x 598 x 598 x 598 x 598 x 598 x
598 x 598 x 598 x 598 x 598 x 598 x
598 x 598 x 598 x 598 x 598 x 598 x 598
Now group up fot 598 x 598 x 598 = 213847192
213847192 x 213847192 x
213847192 x 213847192 x
213847192 x 213847192 x 598
now see 2 x 2 x 2 x 2 x 2 x 2 x 8 = even number
The anwer that you linked to has a typo, they found that:
598 x 598 x 598 = 213847129 instead of 213847192
2006-12-08 13:03:32
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answer #2
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answered by n_m_young 4
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The original question asked for 19^598, not 598^19. It's just that some of the answerers started started answering 598^19. It is indeed true that 19^598 has 1 as its last digit. Cheers!
As a note, it goes to show how important it is for answerers to thoroughly read the question and all references provided ;)
2006-12-08 12:52:42
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answer #3
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answered by bag o' hot air 2
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It is not possible.
598^19 = (2*249)^19= 2 * [(2^18) * (249^19)]
2 times ANY integer is an even integer, by definition, since even numbers are divisible by 2.
Done.
However, 19^598 is odd, since 19 is odd, and odds multiplied by odds are likewise always odd. Remember that an odd number cannot contain a factor of 2. Thus no number of odds multiplied by one another can ever have a factor of two, and so, cannot be even.
2006-12-08 12:52:12
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answer #4
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answered by Jerry P 6
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since 598 is an even number 598^19 is an even number. Not an odd number
2006-12-08 12:51:38
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answer #5
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answered by ATS 2
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The question asked "What is 19 to the power 598?" which means 19^598 (not 598^19).
598^19 is, of course, even.
2006-12-08 17:22:19
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answer #6
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answered by Anonymous
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It's an even number. If I multiply 598 or any
even number by itself any number of times
I still get an even number!
2006-12-08 14:26:13
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answer #7
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answered by steiner1745 7
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298^19 (read as "298 to the power of 19") is an even integer, but
19^298 (read as "19 to the power of 298") is an odd integer.
I think you misinterpret the wording of the problem.
^_^
2006-12-08 21:45:49
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answer #8
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answered by kevin! 5
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An even number times any number is always even. An even number raised to any power is even.
2006-12-08 12:45:51
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answer #9
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answered by Barkley Hound 7
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it is an even number
2006-12-08 12:46:58
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answer #10
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answered by raj 7
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