Do I need to rewrite this equstion in slope intercept to graph it?
The equation is 5x+5y-13=0
When I work this problem I get
y = -x + 13/5
Can anyone help?
2006-12-08 03:32:29 · 6 answers · asked by Ken H 1 in Science & Mathematics ➔ Mathematics
You're ready to graph this now.
It crosses the Y axis where X = 0, or 13/5.
It has a slope of -1, so goes down one for each increase of X by one. I.e. when X = 13/5, Y = 0 and it crosses the X axis.
2006-12-08 03:36:38 · answer #1 · answered by moto 3 · 1⤊ 0⤋
of course. if you need to determine the slope of a following equation,then change the given equation into the slope intercept form with an equation of y=mx+b. The answer is y=-x+13/5.
m=-1, m is the point where the line is on the x-axis. then b now is your y intercept.your y is improper fraction. change that into mix fraction for you can now be able to put the point where it supposed to be lies. then you can finally graph that equation
2006-12-08 03:43:41 · answer #2 · answered by Anonymous · 1⤊ 0⤋
if u rewrite it is easier, oyur solution is correct, because is a line you can draw it finding the value of y with 2 diferent values of x.
Anpother way is that slope is -1 that mean that every change of 1 in x decrements the value of y in one and the line intercpt when y=13/5 and x=0
2006-12-08 03:37:29 · answer #3 · answered by PaD 2 · 0⤊ 0⤋
you make it easy to graph when you write it in the form
y=mx+b where m = slope of the straight line and b=the "y" intercept on the graph
you can always solve by assuming value for "x" and slolving for "y"but then you need 2 point to establish a straight line whereas in above you know the "y" intercept and the slope and you can draw it immediately
2006-12-08 03:43:25 · answer #4 · answered by jojo 2 · 1⤊ 0⤋
5x+5y-13=0
5y=13 - 5x
y = 13/5 -x
=>
m = -1
₢
2006-12-08 03:50:27 · answer #5 · answered by Luiz S 7 · 0⤊ 0⤋
you have done it
the slope is -1 and the y intercept is (0,13/5)
2006-12-08 03:37:25 · answer #6 · answered by raj 7 · 1⤊ 0⤋