Two force, F1=(3i +4J)N and F2 = (6i + 8J)N act on a particle. The resultant of these 2 forces is F.?

Question

The unit vectors i and j are perpendicular.

a) Find F?

b) Find the magnitude of F?

c)Find the acute angle between F and the unit vector i?

Answer 1

Given that those two are vectors:

F1+F2=3i+6i+4J+8J

a) F=9i+12J

b) The magnitude of the resulting vector is: |F|=[(9)^2+(12)^2]^1/2, which means that |F|=15.

c) Being that the i and J components of the force are cathetes for a triangle, in which |F|=15 is the hypotenuse, the angle between F and unit vector i is:

θ=ATAN(12/9)
θ=53.1301°

Good luck!

Answer 2

think of geometry! the consequent is the diagonal of a sq.. the two adjoining sides are the equivalent forces. remember that the element of a sq. is a million/sqrt(2) circumstances the diagonal! Or (0.707) x the diagonal! So the stress is (0.707) x a hundred and eighty pounds or 127.3 pounds i might get excitement from it in case you voted this a 5 famous individual answer extremely than leaving it as much as an ARBITRARY vote. once you opt for a terrific answer you come back 3 factors. You get NO factors back in case you permit it bypass to a vote.

Answer 3

The components of i are 3+6 = 9
The components of j are 4+8 = 12
Force F = 9i + 12j
Magnitude of F =|F| = sqrt(9^2 + 12^2) = sqrt225 = 15
Tan theta = 12/9 = 1.3333
theta = 53.13 deg

Answer 4

a) F = 3i+4j + 6i+8j = (9i + 12j)N
b) |F| = sqrt(9^2 + 12^2) = 15N
c) Let the angle be r.
tan r = 12/9
r = 53.13 degrees

Answer 5

Well its 4.07pm here in the UK, on a Friday so maybe a slim chance of getting an answer to that question from these here parts.....

Answer 6

b

Answer 7

I knew it.... you wont give up eh?