R is directly proportional to the length of the wire and inversely proportional to the area of the cross section of the wire/
R = p l / A
Note: It is not p but rho
rho is the constant called resistivity
So resitance decreases with increase in area of cross section
2006-12-08 03:41:07
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answer #1
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answered by shubhopriyo 2
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You will need a formula to understand the answer. R = pL / A where R is the resistance p (Greek letter rho) is the resistivity which chiefly depends on the material of which the wire is made L = the length of the wire A = cross sectional area Since R and A are inversely proportional if A (cross sectional area ) is larger then Resistance is less. So the larger the diameter of the wire the less the resistance.
2016-03-28 23:12:35
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answer #2
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answered by Anonymous
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The electrical resistance of a conducting wire varies in inverse proportion to its cross-sectional area, i.e. the bigger the area, the smaller the resisrance, and the smaller the area, the bigger the resistance. Think of electrical resistance as the force offered to the flow of water in a pipe. The wider the area of the pipe, the more water will flow through it and vice-versa.
2006-12-08 03:01:26
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answer #3
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answered by Paleologus 3
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Rsistance is inversely proportional to cross section. Double the area and you cut the resistance in half.
2006-12-08 02:55:46
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answer #4
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answered by Gene 7
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I think It is an inverse relation, the larger the crossection, the lower the resistance and vice versa
2006-12-08 02:48:46
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answer #5
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answered by b_prince 3
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You two look quite alike, did you notice that???
2006-12-08 02:52:10
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answer #6
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answered by chazzer 5
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