on the moon, acceleration due to gravity is about 1.6m/sec^2. If you drop a rock...?

Question

on the moon with initial velocity 0, what are the formulas for velocity v(t), and distance s(t).

thanks!

Answer 1

v = 1.6t

s(t) = (1/2) * 1.6 * t^2

Answer 2

S= ut + 0.5*g*t^2
Time taken , t is inversely proportional to the square root of accln due to gravity.

t(moon)/t(earth)= [ g(earth)/g(moon)] ^0.5
THerefore t(moon) = t(earth) * 6^0.5

Now V = 0.5* 1.6 *t
s = 0.5*1.6*t^2