How do I get the antiderivative of (1+y^2/y)? What is it? Thanks!?

Answer 1

antiderivative of (1+y^2/y)

integral (1+y^2/y)dy
=integral (1+y)dy
=y +(1/2)*y^2

Answer 2

If on the other hand, you really meant (1+y²)/y, then this equals 1/y + y and the antiderivative is lny + y²/2 + C.

Answer 3

antiderivative = integral

∫(1+y²/y)dy =
∫(1+y)dy = y + (1/2)y² + c

or
∫(1+y²)/y dy =
∫1/y dy +∫y²/y dy =
∫1/y dy +∫y dy = ln y + (1/2)y² + c

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