6/(x-2) - 5/(x+2)
2006-12-08 01:54:49 · 5 answers · asked by barrelracincowgirl 2 in Science & Mathematics ➔ Mathematics
First you need to understand this is not an equation because there is no "=" sign. It is an expression or number phrase. OK, now that I have that off my chest -- the common denominator is
( x - 2 ) * ( x + 2 )
6 / ( x - 2) + (-5) / ( x + 2) I made the subtraction problem into addition of the opposite.
6 (x + 2) / ( x - 2 ) ( x + 2 ) + (-5) ( x - 2 ) / ( x - 2 ) ( x + 2 ) (change to like fractions)
6x + 12 + (-5x ) + 10 / ( x - 2 ) ( x + 2 ) (multiplied in numerators)
x + 22 / ( x - 2 ) ( x + 2 ) (added like terms in numerator)
2006-12-08 02:26:45 · answer #1 · answered by sunshinesdaddy 2 · 1⤊ 0⤋
What you have given ius an algebraic expression If it has an equation it should have an = sign . Hope you get it.
The expression can be simplified to (x+22)/ (x^2-4)
2006-12-08 10:14:24 · answer #2 · answered by Venkateswaran A 2 · 0⤊ 0⤋
6/(x-2) - 5/(x+2) =
[6(x+2) - 5(x-2)] / [(x-2)*(x+2)] =
(6x+12-5x+10) / (x²-2²) = (x+22) / (x²- 4)
₢
2006-12-08 10:37:43 · answer #3 · answered by Luiz S 7 · 0⤊ 0⤋
No
6/(x-2) - 5/(x+2)
[6(x+2)]/[(x-2)(x+2)] - [5[(x-2)]/[(x+2)(x-2)]
(6x+12)/(x^2 + 2x - 2x - 4) - (5x-10)/(x^2 + 2x - 2x - 4)
(6x+12)/(x^2 - 4) + (-5x+10)/(x^2 - 4)
(6x+12-5x+10)/(x^2 - 4)
(x+22)/(x^2 - 4)
2006-12-08 11:01:05 · answer #4 · answered by Andy M 3 · 0⤊ 0⤋
I think it should be
x+22 / (x-2)(x+2)
2006-12-08 09:59:08 · answer #5 · answered by vai 2 · 0⤊ 0⤋