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The questions say to:

Find the slope of a line that is prependicular to the graph of 2y=4x-6

and the other says:

Find the slope of a line that is parallel to -2x-5y=10.

I have NO clue what to do.

2006-12-08 01:12:49 · 11 answers · asked by living4jesus 1 in Science & Mathematics Mathematics

11 answers

First question: 2y = 4x - 6

2y = 4x - 6 --solve for y--> y = (4/2)x - (6/2) --> y = 2x - 3

slope (m) = 2

Find perpendicular slope = (-1/m) = (-1/2) = -0.5

Second question: -2x - 5y = 10

Solve for y...
5y = -2x - 10
y = (-2/5)x - (10/5)
y = -0.4x - 2

The slope of a line that is parallel to the above equation would have the same slope, thus would equate to -0.4

2006-12-08 01:25:08 · answer #1 · answered by Cinna B 2 · 0 0

At some time your teacher gave you the formula
y = mx + b
That's important for this problem. You have to find m, the slope of the line. All parallel lines have the same slope. The slope of perpendicular lines is the negative reciprocal (Don't panic, I'll explain that.)
Problem 1. solve for y. Divide by 2. y = 2x - 3 The slope is 2. To find a perpendicular slope, change the sign and invert. It is 2/1, so the perpendicular is -1/2
Problem 2 Solve for y. -5y = 2x + 10, so y = -2/5x - 2. m, the slope is -2/5 so the slope of a parallel line is also -2/5

Next time try to follow the examples in the book. I bet you can figure out this stuff yourself, and you will remember it better. Good luck!

2006-12-08 01:25:04 · answer #2 · answered by teacher2006 3 · 0 0

Slope/intercept form is y=mx+b. Get them in this form 1st.
In 2y=4x-8 divide all terms by 2 to get y=2x-4.
The slope of this equation is 2. The slope of a perpendicular line will be -1/2.

In -2x-5y=10, add 2x to both sides to get
-5y=2x+10. Then divide every term by -5 to get y=-2/5x-2. The slope of the line is -2/5, thus a parallel line will have the same slope (slant).

Have a great holiday!
Eds

2006-12-08 01:25:47 · answer #3 · answered by Eds 7 · 0 0

Firstly I assume you know what perpendicular and parallel are?

2y = 4x - 6 so y = 2x-3. This means the gradient of the line is 2 so any line that is perpendicular to this must cross it at 90 degrees. The general rule is that if a line is y = mx + c then a perpendicular line is y = (-1/m)x +c

So for this one, a line could be y = (-1/2)x + 6 or y = (-1/2)x - 2

For parallel, it just has to have the same gradient so -2x-5y = 10 so rearrange to get y = 2 - (2/5)x so other lines would include y = (-2/5)x +1 or y = (-2/5)x -2

2006-12-08 01:23:47 · answer #4 · answered by Status: Paranoia 4 · 0 0

For the second question:

If two lines are parallel, it means they have the same slope, that way they'll never intercept each other along their separate ways.

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept.

So, the slope for both parallel lines would be:

5Y=-2X-10
Y=(-2/5)X-2

Slope m=(-2/5).
_______________________________________

For the first question, if two lines are perpendicular, the multiplication of their slopes equals -1. So first, we need to find one of the line's slope:

2Y=4X-6
Y=2X-3

The first line's slope is m1=2. Now:

m1*m2=-1
m2=(-1/2)

The slope for a line that's perpendicular to 2Y=4X-6 would be (-1/2).

Good luck!

2006-12-08 01:28:55 · answer #5 · answered by Anonymous · 0 0

The basic formula for a line is y = mx + b
where m is the slop and b is the y-intercept (x = 0)

So know this, solve for y
2y = 4x - 6 : divide both sides by 2
y = 2x - 3 : slope (m) = 2
Since you want the perpendicular slope, the sign is oppisite

so the slope of the perpendicular line is -2

Do the same for the other, except that parallel lines have the same slope.

2006-12-08 01:23:17 · answer #6 · answered by SHAWN G 3 · 0 0

a)
2y = 4x - 6
y = 2x - 3, slope = 2
slope of line perpendicular is just the negative reciprocal of the slope of the original line.
Therefore, slope(perpendicular line) = -1/2
b)
-2x - 5y = 10
-5y = 2x + 10
y = -2x/5 - 2 , slope = -2/5
the lines parallel to it must have slopes equal to the slope of the original line.
Therefore, slope(parallel line) = -2/5

2006-12-08 01:22:59 · answer #7 · answered by Joe Mkt 3 · 0 0

1)
2y=4x-6
y = (4x-6)/2
=>
m = 4/2 = 2

slope of the perpendicular line:
m' = -1/2

2)
-2x-5y=10
-2x-10=5y
y = (-2x-10)/5
=>
m = -2/5

slope of the parallel line:
m' = -2/5

2006-12-08 01:35:00 · answer #8 · answered by Luiz S 7 · 0 0

first of all, the slope is the number in front of x
1. perpendicular to 2y = 4x - 6
regalar form is y = 2x -3
when its perpendicular, the slope is the negative reciprocal of the other.
So basically, since the form of the line is y = -1/2x + b, the slope is -1/2

2. parallel to -2x -5y = 10
put y by itself: -5y = 2x + 10
make it in regualr form: y = -2/5 + 2
since it's parallel, it's the same slope: -2/5

2006-12-08 01:19:37 · answer #9 · answered by Luna 4 · 0 0

1.2y=4x-6
dividing by 2
y=2x-3
slope=2
slope of perpendicular line will be the negative inverse of 2
=-1/2

2.-2x-5y=10
adding 2x
-5y=2x+10
dividing by -5
y=(-2/5)x-2
slopes of parallel line are equal
so slope of the required line=(-2/5)

2006-12-08 01:26:05 · answer #10 · answered by raj 7 · 0 0

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