How do you integrate e^(x/4) ?

Answer 1

Integral(e ^ (x/4) dx)

let u = x/4, du = dx / 4, dx = 4 du

Integral(e ^ (x/4) dx) = 4 Integral(e ^ u du) = 4e^u + C = 4e^(x/4) + C

Answer 2

For a linear function u(x) = px + q
integral e^u(x) dx = [1/u'(x)].e^u(x) + c
where c is an arbitrary constant of integration. In this case integral e^(x/4) dx = 4e^(x/4) + c

to assure yourself differentiate the answer 4.e^(x/4) + c
then you will have e^(x/4).

Answer 3

easy the integate of e^u is e^u /(du/dx )

u= 4x so du/dx = 4

and the integral is (e^4x)/4

Answer 4

Joe Willy Neckbone says, "I don't rightly know the answer to your question, but I will be right here waiting for you to ask a question that I do know the answer to."

Answer 5

∫e^(x/4) dx =

u = x/4
du = dx/4
4du = dx

=>
∫e^(x/4) dx = 4∫e^u du = 4e^u + c

=>
∫e^(x/4) dx = 4e^(x/4) + c

₢

Answer 6

int(e^ax dx) = e^ax / a + c



Luiz S answer is so wrong it's amazing.