What distance would the truck trave in this interval?

Question

An ice cream truck is mobing along 20m/s (its initial velocity.) It then speeds up (accelerates) for 5 seconds 8m/s2. What distance would the truck trave in this interval?

Answer 1

2 or 3 houses. Til the next batch of screaming kids emerge.

Kids rule.

Answer 2

Since it accelerates at a constant rate, its average velocity is just the average of its initial and final velocities. The initial velocity is 20 m/s. It accelerates at 8 (m/s)/s (a more intuitive way of writing 8 m/s^2 for this problem) for 5 seconds, so in that time it added 40 m/s, making the final velocity 60 m/s. The average of 20 and 60 is 40, so that's the average velocity. Now you just multiply the average velocity by the time, and you find that he travelled 200 m.

Answer 3

using II equation of motion ie. S=ut + (0.5)att
s=diatance travelled
u=initial velocity
t=time taken
a=accleration
tt=t square=square of time taken= t multiplied by t
using this we get distance travelled = 200m