I am in my third year of calculus, and I am annoyed that for some unknown reason I get y = 2(x - 2)^2 - 4 as the answer-- yet the book says its wrong. Someone tell me this is a typo and that I am not living in the twilight zone.
2006-12-07 22:57:17 · 6 answers · asked by Comrade 2 in Science & Mathematics ➔ Mathematics
it's y= 2(x-2)^2 +4
y = 2x^2 - 8x +12
y = 2 ( x^2 - 4x + 6)
y = 2 (x^2 - 4x + 4 + 2)
y = 2 [(x-2)^2 +2]
y = 2(x-2)^2 +4
2006-12-07 23:19:24 · answer #1 · answered by Avand F 2 · 0⤊ 0⤋
y = 2x² - 8x + 12
y - 6= 2(x² - 4x + 6- 6. . .Isolate the - 6
y - 6 + 4 = 2(x² - 4x + 4) . . .x² - 4x + 4. ..Perfect square
y - 2= 2(x - 2)(x - 2)
y - 2= 2(x - 2)²
- - - - - -s-
2006-12-08 08:40:40 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
y= 2(x^2-4x+4)+12-8
you add and subtract number nessesary for it to be a perfect square formula of a^2+2ab+b^2
y = 2(x-2)^2+4
2006-12-08 07:06:25 · answer #3 · answered by yozja_18 1 · 0⤊ 0⤋
should be '+4' not '-4'
2006-12-08 07:01:44 · answer #4 · answered by mitzy 5 · 0⤊ 0⤋
((2x-4)^2+8)/2=y
2006-12-08 07:59:10 · answer #5 · answered by Bahram E(IGS TEAM) 1 · 0⤊ 0⤋
y=2(x^2-4x+6)
y=2(x-2)(x-2)
2006-12-08 07:57:41 · answer #6 · answered by Roi k 2 · 0⤊ 0⤋