it is in calculus
2006-12-07 22:07:06 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
it is 1/(2*sqrtx)
proof:
y=sqrt(x)=x(to the power 1/2)
formula:d(x to the power n)=n(x to the power n-1)
hence,
apply n=1/2.
and u get the answer.
2006-12-07 23:19:26 · answer #1 · answered by physics 2 · 0⤊ 0⤋
Yes, but in general, use the power rule. The derivative of x^n for any n at all except for 0 is nx^(n-1).
2006-12-08 09:34:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋
y=squareroot(x)=x^(1/2)
Hence
y'=1/2* x^(1/2 - 1)
or
y'=1/(2*squareroot(x))
2006-12-08 06:10:41 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
let y = square root of x = x^(1/2)
dy = (1/2)[x^(-1/2)]
= (1/2)[1/x^(1/2)]
= x^(1/2) / 2x
= square root of x divided by 2x
2006-12-08 08:05:36 · answer #4 · answered by Sheila 2 · 0⤊ 0⤋
d/dx(x^1/2)=1/2*x^(-1/2)
d/dx(x^n)=nx^(n-1)
2006-12-08 06:12:41 · answer #5 · answered by viharika v 1 · 0⤊ 0⤋