In a class of 38 students, the number of females is two more than five times the number of males. How many females are there in the class! Does anyone know how to solve this! Thanks
2006-12-07 18:16:02 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6 males, 32 females
since 38 - the number of males equals the number of males times 5, plus 2:
38-x=5x+2
add x to each side
38=6x+2
subtract 2 from each side
36=6x
x=6 (males)
6*5=30
30+2=32 (females)
32+6=38
2006-12-07 18:20:16 · answer #1 · answered by jabber_wok 2 · 0⤊ 0⤋
Let x be the number of males in the class. Then the total number of students in the class is:
x + (5x +2) = 6x + 2 = 38
6x = 36
x = 6
5x + 2 = 5*6 + 2 = 32
The number of males is 6 and the number of females is 32.
They never had lopsided classes like that when I was in school.
2006-12-08 02:34:16 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
30 +2 females
6 males
5 X 6 = 30+2 =32
32+6 =38
2006-12-08 02:21:44 · answer #3 · answered by bullfiter 1 · 0⤊ 0⤋
6 males, 32 females
2006-12-08 02:20:05 · answer #4 · answered by arj7002 2 · 0⤊ 0⤋
g + b = 38
g = 5b+2
substitue in first equation
5b+2 + b = 38
6b+2=38
6b=36
b=6
then girls = 6*5+2=32
assume b=6, g then = 5*6+2 = 32
g+b
2006-12-08 02:23:33 · answer #5 · answered by bkc99xx 6 · 0⤊ 0⤋