Find X if the line through (1,2) and (X,3) has a slope of 1/4.?

Question

just need to know how to find x in the problem above? thanks

Answer 1

The slope "m" of the line containing the points (a,b) and (c,d) is
m = (b - d)/(a - c)

Therefore, we can substitute our information a = 1, b = 2, c = X, d = 3 and m = 1/4. Thus,
1/4 = (2 - 3)/(1 - X)

We add
1/4 = -1/(1 - X)

We cross multiply
1 - X = -4

We transpose 1
-X = -5

Therefore,
X = 5

^_^

Answer 2

Keep in mind that the slope formula is

m = (y2 - y1) / (x2 - x1)

So all we have to do is plug in (1,2) for (x1,y1) and (x,3) for (x2,y2)

m = (3 - 2) / (x - 1)

But we know the slope; m = 1/4, therefore

1/4 = (3 - 2) / (x - 1)

Multiply both sides by (x-1) to eliminate the fraction on the right hand side.

(x-1)/4 = (3 - 2)

Multiply both sides by 4 to get rid of the fraction on the left hand side.

x - 1 = 4(3 - 2)

Solve normally.

x - 1 = 4(1)
x - 1 = 4
x = 5

Answer 3

y2-y1/x2-x1=m (slope)
so,
3-2/x-1=1/4
1/(x-1)=1/4
what does it take to get 4 on the bottom?
5 (5-1=4)
s0, 1/4
x=5
(5,3) would be the point