s² + 4st -12t²
2006-12-07 18:06:33 · 6 answers · asked by Sally 1 in Science & Mathematics ➔ Mathematics
(s+6t)(s-2t)
2006-12-07 18:08:26 · answer #1 · answered by pigley 4 · 0⤊ 0⤋
s² + 4st -12t²
In this equation the general rule is to find the factors of the last number which is 12.
You need to find factors which when added must give the middle number (+4) and when multiplied must give the last number (-12).
In this case the factors are -2 and +6. When you add these two factors you get the middle number ( i.e. -2+6 = 4). When you multiply these two factors you get the last number i.e. (-2) x (+6) = -12.
With this found you apply the general algebra rule as follows:
s² + 4st -12t² = (s-2t)(s+6t)
2006-12-07 18:37:50 · answer #2 · answered by pyokerakawonga 2 · 0⤊ 0⤋
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2006-12-07 18:15:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(s-2t) (s+6t)
2006-12-07 18:11:43 · answer #4 · answered by bullfiter 1 · 0⤊ 0⤋
(s+6t)(s-2t)
2006-12-08 16:11:18 · answer #5 · answered by jerryinchelsea 2 · 0⤊ 0⤋
(s+6t)(s-2t)
2006-12-07 18:11:35 · answer #6 · answered by arj7002 2 · 0⤊ 0⤋