opposed to Tails) I'm learning probabilities, and I'm not sure what to apply to this question. The combination formula? Draw a table? Can anyone give the answer and explain all the steps please?
2006-12-07 17:44:57 · 5 answers · asked by omgwtf1980 2 in Science & Mathematics ➔ Mathematics
Thanks a ton you guys, I really appreciate it.
2006-12-07 17:58:20 · update #1
I use "reverse logic" for this one:
P(tails) = 0.5
P(5tails) = 0.5^5
P(at least 1 Head) = 1 - P(5tails) = 1-0.5^5
P(at least 1 Head) = 0.96875
2006-12-07 17:58:27 · answer #1 · answered by Helmut 7 · 1⤊ 0⤋
The probability is one minus the probability of all tails:
1 - P(5 tails) = 1 - 1/(2^5) = 1 - 1/32 = 31/32
2006-12-07 17:52:28 · answer #2 · answered by Northstar 7 · 1⤊ 0⤋
The quickest way to approach this problem is to think about what is NOT going to happen. In this case, that is getting tails 5 times in a row. Getting at least one head is the same as NOT getting 5 tails.
One of the rules of probability is that the probability of an event not happening is one minus the probability of that event happening, so Pr(At least one head) = Pr(not 5 tails) = 1 - Pr(5 tails).
2006-12-07 17:55:23 · answer #3 · answered by Tim N 5 · 0⤊ 0⤋
the probabilty of getting a head when you flip a coin once is 1/2. Cos the sample space consists of {Head, Tail} and you are choosing from one of it.
Probality of getting atleast one head=1-probability of gettin no head.
when a coin is flipped 5 times, total no. of outcomes 2^5.
And getting no heads is one event.
therefore, probability of getting no head is 1/{2^5}
therefore the answer is
1- [1/{2^5}]
2006-12-07 17:52:02 · answer #4 · answered by Srideepti Kidambi 1 · 2⤊ 0⤋
50% chance plus or minus 1
2006-12-07 17:54:37 · answer #5 · answered by badbill1941 6 · 0⤊ 2⤋