I took physics last year and am helping a friend with this problem. I thought it was easy, but keep getting the answer to be 3096.1875, which is wrong, can someone help me.
A 10.00 kg block hangs from a spring. A 110 g body hung below the block stretches the spring 3.20 cm farther.
What is the spring constant?
2006-12-07 17:20:55 · 2 answers · asked by Michael E 2 in Science & Mathematics ➔ Physics
Really, you don't need to worry about the original weight on the spring; it will just change the origin, as the force is linear in x.
So, F= k x, or k = F / x
Here, force is 0.11 kg * 9.8 m/s^2 = 1.078 N
x=3.2 cm = 0.032 m
So k = F/x = 33.69 N/m
2006-12-07 17:27:51 · answer #1 · answered by Michael S 2 · 2⤊ 0⤋
Assuming that it's still in the linear region where the spring constant is F/h then
F = mg = 0.110*9.8 = ..... Newtons
h = 0.0320 m
I don't have my calculator handy.
You probably have a units problem. Keep in mind for the SI system, Mass is kg, F is newtons, distance is m
2006-12-08 01:27:46 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋