in 1970 t=0, so plug 0 into your two equations. then take the second equation, for the total sales, and divide it by the answer you got in the first equation to find the average.
use t=10 for 1980, ,and use t=20 for 1990, follow the same method.
2006-12-07 17:00:26
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answer #1
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answered by leksa27 2
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A = [2200 + 400t/(24 - t)]/[10,000 + 5500t/(35 - t)]
A = [(52,800 - 2200t + 400t)/(24 - t)]/[(350,000 - 10,000t + 5,500t)/(35 - t)]
A = [(52,800 - 1,800t)(35 - t)]/[(24 - t)(350,000 - 4,500t)]
A = (1,848,000 -52,800t - 45,000 + 1,800t^2)/(8,400,000 - 350,000t - 108,000 + 4,500t^2)
A = (18480 -978t + 18t^2)/(84000 - 4580t + 45t^2)
A = (6,160 - 326t + 6t^2)/(28,000 - 1,527t + 15t^2)
A = (6,160 - t(326 - 6t))/(28,000 - t(1,527 - 15t))
A(1970) = $220,000
A(1980) = $245,959
A(1990) = $589,595
2006-12-08 01:41:43
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answer #2
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answered by Helmut 7
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