stuck factoring?

Question

2x² + 6x - xy - 3y

ahh I don't get it! there's four of them!

Answer 1

This is a type of factoring called "grouping"; What you would do is factor the first two terms, and then factor the last two terms, hoping to get something in common.

2x^2 + 6x - xy - 3y

Factor the first two terms

2x(x + 3) - xy - 3y

Factor the last two terms.

2x(x+3) - y(x+3)

Now, notice that you have (x+3) twice? All you have to do is look at these as terms, and factor (x+3)!!

(x+3) [2x - y]

See what I did there? I factored (x+3) out of BOTH terms, because that's what both terms had in common. I know that the terms we're usually used to factoring out are stuff like x^2, 2x, 3, and so forth. But in this case it's (x+3).

If that's too confusing for you, let z = (x+3). Then

2x(x+3) - y(x+3)

becomes

2xz - yz

Now, let's factor z out.
z(2x - y)

BUT z = (x+3), so this is actually

(x+3)(2x - y)

That's the concept of "grouping". You're grouping like terms without realizing.

Answer 2

what does it equal? zero?
2x^2+6x = xy+3y
..............= y(x+3)
(2x^2+6x)/(x+3) = y

you want the zeroes?? it is: 2(x^2+3x)=0 --> x= -3, or 0
Vertical Asymptote at -3
blah

Answer 3

group factor

(2x^2+6x)-(xy-3y)
2x(x+3)-y(x+3)

(2x-y)(x+3)would be your answer

Answer 4

i am a new yahoo user ,i sell some product on yahoo .
this is my yahoo store http://www.llpshop168.com ,if i bother you ,i hope you can forgive me ,thank you for your time .i hope you can give me some suggest about my product.

Answer 5

i agree with Liz S.... Group them together... the first two then the last two.....