suppose a bird drops a nut from a tree. the speed of the falling nut at the moment 50 m above the ground is 42.7 m/s. how tall is the tree? do you need to know the mass of the nut to solve this problem? disregard air resistance.
2006-12-07 15:55:51 · 4 answers · asked by maggie 1 in Science & Mathematics ➔ Physics
assume dropped from rest
Velocity =initial velocity + a*t
42.7=0+a* t
42.7=9.8*t
t=4.357 seconds
distance travel in 4.357 seconds = 1/2 v* t
=.5 *42.7m/s*4.357s =93.02 meters
Tree = 93.02 + 50 = 143.03 meters
2006-12-07 16:07:32 · answer #1 · answered by bkc99xx 6 · 1⤊ 0⤋
Use the equation V^2 - U^2 = 2 a S.
U = 0
V = 42.7 m/s
a = 9.8 m/s^2.
S = [42.7 x 42.7] / {2 x9.8} = 93.025 m.
The height of the tree = 93.025 + 50 = 143 .025 m
2006-12-08 01:17:23 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
If you still don't know that bowling balls and peas fall at the same speed, I recommend that you switch courses.
2006-12-08 00:10:19 · answer #3 · answered by vinny_the_hack 5 · 0⤊ 0⤋
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