how do you find the standard form for (-8,3) m=2?

Question

thank you so much!!

Answer 1

Stardard form is y=mx+c
m = gradient = 2

Let y = 3 and x = -8, given the coordinate (-8,3)
Thus,
y=mx+c
3=2(-8)+c
3=-16+c
c=3+16
c=19

Finally the standard form is
y=2x+19, m=2 and c =19

Answer 2

Recall that slope (m) is equal to

m = (y2 - y1)/(x2 - x1)

Also recall that the equation of a line consists of a y and an x.

All you have to do is form the equation of a line using the slope formula for (-8,3) and (x,y).

That is, we know m = 2, and we know that (x1,y1) and (x2,y2) is equal to (-8,3) and (x,y) respectively. Now we just plug in.

m = (y2 - y1)/(x2 - x1)

2 = (y - 3)/(x - (-8))
2 = (y - 3)/(x + 8)
2(x+8) = y - 3
2x + 16 = y - 3
2x - y + 16 + 3 = 0
2x - y + 19 = 0

That's the line in standard form. You'll be asked to put lines in either standard form or slope-intercept form. Standard form looks like the following:

Ax + By + C = 0 (where A is positive)

And slope intercept form looks like this:

y = mx + b, where m is the slope and b is the y-intercept

Answer 3

put the numbers into point-slope equation.

y-y=m(x-x)

so

3-y=2(-8-x)

distribute the 2, and put the equation into standard form.