first you factor Common Multiple, 2 and receive
2(a²+6a+9)
Now factor and receive
2(a+3)(a+3)
2006-12-07 15:00:32
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answer #1
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answered by Anonymous
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2a² +12a +18 = 2(a² +6a + 9) = 2(a+3)² .
2006-12-07 23:01:33
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answer #2
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answered by Anonymous
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2a^2 + 12a + 18
2(a^2 + 6a + 9)
2(a + 3)^2 or 2(a + 3)(a + 3)
2006-12-07 23:25:27
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answer #3
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answered by Sherman81 6
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we make the X sign as in the pic
and put 2 numbers (on the left side that when we multiply we get (2a²)
and on the left side two nubers when we multiply get 18
on a condition when we multiply the numbers on the same line we get two numbers that their sum (difference incase the last term (18)is -ve) = 12
then we put the middle term's sign as the last term is +ve (we put a simillar sign of the middle term to the great number and a different sign to the smallest in case the last term is -ve)
so we have
2a² +12a +18 =
(2a + 6) + (a + 3)
2006-12-07 23:24:58
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answer #4
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answered by M. Abuhelwa 5
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=2(a^2 + 6a + 9)
= 2(a + 3)(a+3)
2006-12-07 23:01:00
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answer #5
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answered by bkc99xx 6
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2(a^2 +6a+9)
2(a+ 3)(a+3)
2006-12-07 23:00:54
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answer #6
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answered by leksa27 2
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