I already own and love Oh Baby & Viva Glam VI. I want more!!! lol.
2006-12-07 14:39:32 · 7 answers · asked by Miss Anthrope 6 in Beauty & Style ➔ Makeup
Girl, I love M.A.C lipglass too and I am about the same complexion as you and what I have are: Oyster girl, Beux, Luminary, and Morning Glory. Those are so far the only ones that I saw that match my skin tone and don't look to bright. But I've never tried Oh Baby and Viva Glam, so you just told me something new. I'll have to look into that. I hope you look into these as well, I'm sure you will like them. Have a good day!!!
2006-12-08 03:13:24 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Mac Lipglass For Dark Skin
2016-10-19 05:45:32 · answer #2 · answered by ? 4 · 0⤊ 0⤋
ok here goes. I've been a licensed Makeup Artist for 17 years and I can say it must complement your skin tone. No offense to MAC but I don't trust alot of there artist for they are not licensed and are only trained in there line. Go to a Spa or Salon and ask the artist there to show you ALL your right colors. Consultations are usually free and some of them have some great make up lines. GOOD LUCK
2006-12-07 15:04:47 · answer #3 · answered by Alyssa C 2 · 1⤊ 0⤋
My best friend is about your complexion which I think is a nw45 in studio fix. She swears by "oh baby" lipglass shade. I think you should try a few shades at the counter. Red is in right now and there's a shade of red for everyone. For your complexion I would try a crimson red.
2006-12-07 15:51:01 · answer #4 · answered by miss tique 3 · 1⤊ 0⤋
depends on the style u go for..not sure in what colors cause i only use the clear one.. but try the clear with a pigment color..gives ya added choices..=] good luck hun..
2006-12-07 15:44:53 · answer #5 · answered by julie092179 3 · 1⤊ 0⤋
dark skin needs smooth sandy color...like this one
2006-12-07 15:48:54 · answer #6 · answered by ♥BlackDahlia♥ 2 · 1⤊ 0⤋
CYLON a big big news for you!...
:)! http://www.osoq.com/funstuff/extra/extra04.asp?strName=CYLON
2006-12-07 14:53:41 · answer #7 · answered by emh g 1 · 1⤊ 0⤋