i need all the combinations pls try to answer..... i think there are hundreds of combinations pls try to spend time helping me find the combinations..
2006-12-07 14:24:12 · 4 answers · asked by chong t 1 in Science & Mathematics ➔ Mathematics
Are you crazy? There are 8,145,060 possible combinations. Well more than hundreds! We are not going to try and list them all here.
How did I get that, you might ask?
Since there are 45 possible numbers, and you want all of the combinations with six of them, then
45C6 = 45!/(6!*(45-6)!) = 8,145,060
2006-12-07 14:32:25 · answer #1 · answered by blahb31 6 · 0⤊ 0⤋
There are a lot of possible combinations- of course you cannot "find" them all. Assuming you cannot use a number more than once,
Case 1: 2 numbers 1-9, 2 numbers 10 - 45. 9*8*36*35 =90720.
Case 2: 4 numbers 1 - 9, 1 number 10 - 45: 9*8*7*6 * 36 = 108864
Case 3: 3 numbers 10 - 45 36*35*34 = 48240.
You have to subtract all the combinations you overcounted, though. Are you sure you worded the question correctly? Maybe you mean - how many ways can you choose 6 of the numbers 1 - 45? that is a totally different question, and then the answer is simply 45C6.
2006-12-07 14:39:02 · answer #2 · answered by need help! 3 · 0⤊ 0⤋
45C6 = (45!)/(6!(45 - 6)!)
45C6 = (45!)/(6! * 39!)
45C6 = 8145060
however if you can give repeating numbers like 414 or 144, then
45P6 = (45!)/((45 - 6)!)
45P6 = (45!)/(39!)
45P6 = 5864443200
2006-12-07 15:48:16 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
Is this a lottery question?
2006-12-07 14:26:06 · answer #4 · answered by normobrian 6 · 0⤊ 0⤋