Hello. I need help with my Chemistry. I know all of my other questions except this one and one other. The question is: How many electrons in an atom can have the quantum numbers n = 4 and l = 1?
The other question was: When solid sodium chloride (NaCl) is dissolved in liquid water, the sodium ion is attracted to the water molecule's:
A.) negative end, which is hydrogen
B.) negative end, which is oxygen
C.) positive end, which is hydrogen
D.) positive end, which is oxygen
Please explain how you got your answers. thanks
2006-12-07 14:04:53 · 4 answers · asked by ybkid 2 in Science & Mathematics ➔ Chemistry
Pauli's exclusion principle says no two electrons in an atom have have the same set of quantum numbers. Under n and l, there can be m(l) = +1, m(l) = 0, or m(l) = -1. Under each m(l), there can be a positive or negative spin electron. So, there are 6 total.
Sodium ions are positively charged, and are attracted to the negative end of a water molecule. H is positive and O is the negative end.
2006-12-07 14:17:43 · answer #1 · answered by Bruce 2 · 0⤊ 0⤋
6 e- can have n = 4 and l = 1 since n = 4 means the 4th energy level and l = 1 means the "p" sublevel which can hold at most 6 e-
Na1+ is attracted to the negative oxygen end of the polar water molecule.
2006-12-07 14:14:43 · answer #2 · answered by physandchemteach 7 · 0⤊ 0⤋
For a cost of n, the utmost fee of l is n-one million so A and C at the instant are not obtainable (n can't be 0 besides). For a cost of l, the values of ml are -l to +l. So for B, the placement l = 0, ml can't be -one million. for this reason basically D is a obtainable set of quantum numbers. For the 2d portion of your question, 3 is definitely.
2016-10-17 23:22:32 · answer #3 · answered by ? 4 · 0⤊ 0⤋
answer of first question is 6
answer of second ques is B
2006-12-07 14:26:59 · answer #4 · answered by smart-crazy 4 · 0⤊ 0⤋