A pitcher claims he can throw a baseball with as much momentum as a 1.1 g bullet moving with a speed of 4500 m/s. A baseball has a mass of 0:368 kg. What must be its speed if the pitcher's claim is valid? Answer in units of m/s.
2006-12-07 13:26:18 · 2 answers · asked by Maria M 1 in Science & Mathematics ➔ Physics
mass (bullet) x velocity (bullet) < mass (baseball) x velocity (baseball)
velocity (baseball) > 1.1 x 10^(-3) kg x 4500 m/s / 0.368 kg = 13.45 m/s
Seems like a reasonable pitch to me: that's about 30 mph.
2006-12-07 13:43:22 · answer #1 · answered by hevans1944 5 · 0⤊ 0⤋
momentum is mass times velocity. a .0011 kg bullet moving at 4500 m/s has a momentum of 4.95 kg*m/s. So if you have a mass of .368 kg, and you need a momentum of 4.95 kg*m/s, you divide 4.95/.368 to get 13.45 m/s
2006-12-07 13:45:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋