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If you had 100g of water (H2O)...
how many grams of Oxygen would you have?
how many grams of Hydrogen would you have?

2006-12-07 12:50:45 · 5 answers · asked by Anonymous in Science & Mathematics Chemistry

5 answers

100 g H2O gives you 89 g O2 and 11 g H2.

2006-12-07 12:53:23 · answer #1 · answered by physandchemteach 7 · 0 0

Oxygen weighs 16 and each hydrogen 1 so 18 grams is one water. Divide the 100 by 18 to see how much you have and then use a proportion2/9 ths and 8/9ths

2006-12-07 21:02:48 · answer #2 · answered by science teacher 7 · 0 0

Hydrogen and Oxygen are at a 1 to 17 and 16 to 17 mass ratio but there are 2 hydrogens in water so we have a 2/18 ratio to a 16/18 so if we split 100 into 18 parts we get 5.55, so 11.10 gram of hydrogen 88.90 grams of oxygen

2006-12-07 21:00:41 · answer #3 · answered by pechorin1 3 · 0 0

100 grams of water. You would do this by figuring out how many moles of water is in 100 grams. So the molar mass of water is 18grams per 1 mole so 18 grams/1mole. 100/18 ~ 5.56 moles of water right? Since theres only 1 O in H20 it would be 5.56 moles for oxygen and then double moles for hte H2 because its H2. To get hte grams of oxygen you would do 5.56 x the molar weight of oxygen which is 16 g/mol ( you would usually use 32 when there is oxygen gas then it would be 32g/mol) so 16 multiplied by 5.56 is 88.96g. Then Hydrogen would be 5.56 x 2 (H20 <--- has 2 H so it's doubled) 11.12 moles of H. You would multiply the 11.12 by the molar mass of Hydrogen which is one. So you would end up with 11.12 grams of hydrogen

2006-12-07 20:59:19 · answer #4 · answered by John L 1 · 0 0

In every water molecule, there are 2 atoms of hydrogen, and 1 atom of oxygen.

2 atoms of Hydrogen have an atomic mass of about 2.01588 amu
1 atom of Oxygen has an atomic mass of 15.9994 amu

The percent of Hydrogen is therefore 2.01588/18.01528, or 11.189834407236523...%, and you have roughly 11.2 grams.
The percent of Oxygen then is 15.9994/18.01528 or 88.810165592763476...%, and you have roughly 88.8 grams.

2006-12-07 21:06:42 · answer #5 · answered by dennismeng90 6 · 0 0

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