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Ammonia burns in the presence of oxygen gas and a copper catalyst to form nitrogen gas and water vapor.

4NH3(g) + 3O2(g) -------> 2N2(g) + 6H2O(g) dH=-1267kJ

What is the enthalpy change(in terms of kJ) to burn 35.8g of ammonia?

(answer should be reported to 3 sig figs )
Format: +/-XXX

** BEST ANSWER TO THE ONE WHO GETS IT RIGHT **

2006-12-07 12:50:22 · 0 answers · asked by ** i Am hiS giRL ** 5 in Science & Mathematics Chemistry

0 answers

35.8 g NH3 x (mol / 17 g) x (-1267 kJ/mol) = -2670 kJ

2006-12-07 12:58:17 · answer #1 · answered by scurvybc 3 · 0 0

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