7y^2(y^2+y^3+1)
2006-12-07 12:47:40
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answer #1
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answered by chipotle4evr 1
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7y^4+7y^5+7y^2------factor out common term 7y^2
7y^2 (y^2 + y^3 + 1)-----rearrange in order
7y^2 (y^3 + y^2 + 1) this is it for integers.
2006-12-07 12:51:34
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answer #2
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answered by smaatgg 2
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7y^2(y^2+y^3+1)
2006-12-07 12:52:16
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answer #3
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answered by Binna S 1
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7y^2(1+y^2+y^3)
2006-12-07 12:47:55
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answer #4
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answered by raj 7
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(2x+7y)(x-y) mul the two(7) = 14 ingredient the 14 a million x 14 2 x 7 which pair provides or sub to get the 5 interior the middle term? 2 and 7 to get a +5 you opt for -2 and +7 rewitre the trinomial changing the 5 with -2xy and 7xy 2x² -2xy +7xy – 7y² now team and ingredient (2x² -2xy) +(7xy – 7y²) 2x(x-7) + 7y(x-7) ingredient out the x-7 (x-7)(2x+7y) wish this helped!!!
2016-10-14 05:57:05
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answer #5
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answered by pape 4
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7y^4 + 7y^5 + 7y^2 =7y^11
2006-12-07 12:54:44
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answer #6
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answered by Kevin H 7
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7y^2(y^3+y^2+1)
By the way, Kevin H, you can't add the exponents if you are adding the numbers--you have to multiply them (the numbers of course, not the exponents).
2006-12-07 12:48:04
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answer #7
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answered by dennismeng90 6
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7y^2(y^2+y^3+1)
If this was a function and y was a function of x instead of the usual reverse, then the derivative of this function, using the difference quotient formula or power rule, would be
28y^3+35y^4+14y or, simplified,
y(28y^2+35y^3+14); this is very handy if you wanted to plot the slope of this function by plugging in various points and plotting them.
2006-12-07 12:54:20
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answer #8
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answered by Anonymous
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uuhh 7y^2(y^3+y^2+1) ??
2006-12-07 12:52:10
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answer #9
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answered by answerQuest 2
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