Simplify and evaluate (2^2x^5y^-3z^4/4^0x^-2y^-8z^5)^3?

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Simplify and evaluate (2^2x^5y^-3z^4/4^0x^-2y^-8z^5)^3?

2006-12-07 12:21:33 · 3 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics

3 answers

(2^2x^5y^-3z^4 / 4^0x^-2y^-8z^5)^3 =
Because of the zero in the denominator, the denominator will convert to 1.
(2^2x^5y^-3z^4 / 1)^3 =
(2^2x^5y^-3z^4)^3 / 1 =

This is as far as I can take it for you without more information.

2006-12-07 13:03:50 · answer #1 · answered by Brenmore 5 · 1⤊ 0⤋

Not sure what you mean but I do know the denominator is 1. so the ans is the numerator.

2006-12-07 20:32:52 · answer #2 · answered by smaatgg 2 · 0⤊ 0⤋

2^2x^5y^-3z

2006-12-07 20:28:02 · answer #3 · answered by haha 1 · 0⤊ 0⤋