1. (-2-5i)(8+7i)
2. (3+i)/(5+6i)
2006-12-07 12:15:25 · 5 answers · asked by SICK MY DUCK! 1 in Science & Mathematics ➔ Mathematics
1. (-2-5i)(8+7i) = -16-14i-40i+35 = 19-54i
2. (3+i)/(5+6i) = (3+i)(5-6i)/(5+6i)(5-6i) = (15-18i+5i+6)/(25+36) =(21-13 i) / 61 = 21/61 - 13/61 * i
when dividing complex numbers, multiply by the conjugate of the denominator. i^2=-1.
2006-12-07 12:19:10 · answer #1 · answered by need help! 3 · 0⤊ 0⤋
1. 2i x 6
2. 8 x 7i
2006-12-07 12:20:25 · answer #2 · answered by russel_gario 2 · 0⤊ 0⤋
regulations of exponents (2a^3y)^3(3a^2 y^2)^2 8a^9 y^3 cases 9a^4 y^4 = 72a^13 y^7 capacity to a capacity multiply the exponents multiply powers upload the exponents it in truth skill 2a^3 y cases 2a^3 y cases 2a^3 y cases 3a^2 y^2 cases 3a^2 y^2
2016-11-24 22:04:07 · answer #3 · answered by mink 4 · 0⤊ 0⤋
1. 19-54i
2. Sorry, forgot dividing....
2006-12-07 12:17:52 · answer #4 · answered by Anonymous · 0⤊ 1⤋
go on www.quickmath.com
2006-12-07 12:17:01 · answer #5 · answered by greenpotterboy 2 · 0⤊ 0⤋