A normal woman whose father was color blind marries a color blind man. They produce a son and a daughter.?

Question

What is the probability that: a) the daughter is color blind b) the son is color blind

Answer 1

There are so many different kinds and causes of color blindness that it is almost impossible to answer the question without more facts. However many types are sex linked so the probability of the son being color blind would be greater than the daughter.

Answer 2

okay, the "normal woman" aka the mother is actually a carrier for the colorblind gene because her father was colorblind and he definitely gave her a mutant X. Btw color blindness is x-linked and since she is "normal" this means she has one wildtype X and one mutant X (from her dad).

color blind man can only give a mutant (colorblind x) to his own daugthers

knowing this, we can figure that 1/2 of daughters will be colorblind. to be colorblind, women must have to 2 defective X chromosomes. they will always get a mutant chromosome from dad, but only get it 1/2 the time from mom.

also, 1/2 of the sons will be color blind. basically same reasoning as before. dad gives Y to son, so he doesnt matter in colorblind trait. mom can either give a normal X or a mutant X.

Answer 3

I'm assuming that color blindness is X linked?

Call it b for color blindness.
The woman is Bb
The man is b/Y (the Y chromosome)

So Bb x b/y ===> boys B/Y and b/Y, girls are B/b and b/b

a) daughter color blind is 50% probability
b) son color blind is also 50%

Answer 4

a) the mother of the color blind man is definitely XCXc because he has to have inherited color blindness gene on the X chromosome (Xc) to be colorblind. Remember, boys inherit their X chromosome from the mother and their Y chromosome from dad. Since colorblindness gene is an X-linked gene, for a boy to be color blind, his mother has to be carrier. b) Since the father of the woman is colorblind, then she must be carrier: XCXc XCXc x XcY 1/4 XCXc + 1/4 XCY +1/4 XcXc + 1/4 XcY 1/4 carrier girl + 1/4 healthy boy + 1/4 sick girl + 1/4 sick boy Therefore there is a 50% chance that their first child is either a colorblind girl or a color blind boy. c) 25%. See the answer to b.

Answer 5

I want to say 4 out of 6 a 6 chance......maybe 5 out of 6 chance for the guy??????? Wild guess.......

Answer 6

it depends on the parents' dominant and recessive genes.

Answer 7

50:50 chance for either sex

Answer 8

do you have more info on what genes the parents carry?