Can anybody please write this quadratic expression in vertex form?

Question

Also give the coordinates of the vertex and the equation of the axis of symmetry.
y = x^2 -12x-3

Answer 1

y + 3 = x^2 - 12x
y + 3 + 36 = x^2 - 12x + 36
y + 39 = (x - 6)^2

Vertex is (6, -39), axis of symmetry is x = 6.

Answer 2

y=x^2 - 12x - 3 is in x^2 + Bx + C form so,

y = (x-6)^2 -39

Vertex: (6,-39); general formula: (b/2,c-(b^2))

Axis of sym: x = 6; general formula; x = (b/2)

Please note, when given Ax^2 + Bx + C, these formulas change. The above only works when A=1.