and what would hapen if i poke it?
2006-12-07 11:29:05 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
My oh my did it take you a loooooooong time to type that question?
2006-12-08 05:48:02 · answer #1 · answered by sftbllr4lf 3 · 0⤊ 0⤋
Using the relation
R = R0 A^(1/3)
we can find the amount of nucleons necessary to be large enough to be seen by the human eye. Here A is the number of nucleons, protons and neutrons, and R0 is 1.3 fm.
About the smallest thing we can see is a photon with a wavelength of 400nm. 1 fm = 1^(-15)m and 1nm = 1^(-9) m. Solving for A gives us
A = (4^(-7) m / 1.3(-15) m)^3
= 2.9 x 10^(25) nucleons
Since the mass of protons and neutrons are about the same, we can use either one to calculate the mass of this nucleus. Both masses are about 1.6x10^(-27) kg. So
M = 1.6x10^(-27)kg * 2.9x10^(25)
~ .046 kg
That is about 2.9x10^(25) amu. To put this in perspective the heaviest nucleus I know of is Lawrencium which has an atomic weight of 2.62x10^(2) amu.
If you poked it, I would guess a BIG boom would happen and you would not be able to poke anything ever again.
2006-12-07 12:34:17 · answer #2 · answered by thegreatdilberto 2 · 0⤊ 0⤋
Well, very thin human hair is visible and that's about 50 microns (50x10^-6) meters. Most atoms are about 1 Angstrom (1x10^-10) meters. It would take around 5000 normal atoms to form the diameter of our new atom and let's say a "normal atom has a mass of 16. If our new atom is a sphere, the volume is 4 x pi x r^3 so the mass of our hog is 16 x 4 x pi x 2500^3. You can do the arithmetic.
2006-12-07 11:42:12 · answer #3 · answered by Gene 7 · 0⤊ 0⤋
well be about 300th of a millimeter if there was 80 billion just don't split it or boom an atomic explodion 20 miles destroyed try it!!!!
2006-12-07 11:40:10 · answer #4 · answered by Steve M 2 · 0⤊ 0⤋