how many C are on the left? Now add a multiplier to make it the same on both sides. Now, how many H are on the left. Add a multiplier to make it the same on both sides. Now do this for the O and then go back and check the C and H and repeat until they all match. Then see if you can factor out some common number on each side in case you over did it.
2006-12-07 11:02:52
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answer #1
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answered by Anonymous
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With these, always leave the most pure to the last.
C60H60 + 75O2 --> 60CO2 + 30H2O
So, there are equal amounts now.
Hope this helps.
Sincerely,
The Chemist, Wee Man.
2006-12-07 19:09:19
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answer #2
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answered by boychuka 3
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C60H60 + 75O2 = 60CO2 + 30H2O
its odd but balanced
i would really like a best ans plz
2006-12-07 19:06:01
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answer #3
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answered by Triple S-sweet 2
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C6H6O+7O2=6CO2+3H2O
2006-12-07 19:05:43
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answer #4
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answered by Gennight42 3
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C60H60 + 90O2 = 60CO2 + 60H2O
2006-12-07 19:03:01
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answer #5
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answered by Helmut 7
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C60H60 + 75O2 => 60CO2 + 30H2O
2006-12-07 19:07:38
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answer #6
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answered by Peter 2
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soda pop.
2006-12-07 19:01:42
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answer #7
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answered by Anonymous
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