A 50 KG Pole Vaulter running at 10 m/s vaults over the bar. Her speed when she is over the bar is 1.0 m/s. Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar...
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I thought I got this question when I was reading it but then it said to find altitude and I was just like ooo kkkkk..... kkkkkk
2006-12-07 10:55:15 · 3 answers · asked by Twilight Is Love 1 in Science & Mathematics ➔ Physics
The first answer I got is rlly confusing!
2006-12-07 11:04:39 · update #1
potential energy + kinetic energy needs to be conserved.
When the vaulter is running, her energy is all kinetic, and is
50 kg * (10 m/s)^2 = 5000 kg m^2/s^2
when she is at bar height, her kinetic energy is only 50 kg m^2/s^2, so there must be 4950 joules of potential energy. which is mass times gravity times height.
So write the equation
4950 = 50 (mass) times 9.8 (gravity) times H (height)
solve for H: h = 4950/50/9.8
(I can estimate without a calculator that 4950/9.8 is about 5000/10 = 500, so I get h about 10 meters. That sounds pretty high, but this is the method.
gravity that is overcome is 9/8 m/s/s
2006-12-07 11:07:38 · answer #1 · answered by firefly 6 · 0⤊ 0⤋
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2016-09-03 10:41:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
This is an energy problem, and the vaulter's mass is irrelevant. Calculate the kinetic energy per kilo when running, and the kinetic energy per kilo over the top of the bar. The difference is the potential energy per kilo due to the vaulter's elevation abover the ground, and from there the problem is trivial.
2006-12-07 11:02:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋