Here is the problem with the possible answers:
Calculate the approxiamte volume of a 0.600 mol sample of a gas at 15.0° C and a pressure of 1.10 atm.
a. 12.9 L
b. 22.4 L
c. 24.6 L
d. 139 L
2006-12-07 10:50:01 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
PV = nRT (ideal gas law)
V = nRT/P
15.0 °C + 273.15 = 288.15 K
V = 0.600 mol *0.0821 atmL/molK* 288.2 K / 1.10 atm
V = 12.9 L
a
2006-12-07 10:59:17 · answer #1 · answered by Peter 2 · 1⤊ 0⤋
1) You have to use the Gas Ideal Law:
PV=nRT
we solve for V (=volume):
V=nRT/P
2) We substitute the corresponding values:
n=0.6 moles
T= 15°C=(15+273.15)=288.15 K
P=1.10 atm
R=0.082 L atm/ K mol
3) V =(0.6)(0.082)(288.15)/1.1
V = 12.9 L
So option a) is the correct volume of gas.
That's it!
Good luck!
2006-12-07 19:08:12 · answer #2 · answered by CHESSLARUS 7 · 1⤊ 0⤋
assuming this is an ideal gas, we can use PV=nRT:
(1.10 atm)*(V) = (0.600mol)*(0.082058L*atm/(mol*k))*(288.15k)
V=12.9L
where T=273.15+15=288.15k (absolute temperature)
2006-12-07 18:57:46 · answer #3 · answered by orca1006 2 · 1⤊ 0⤋