havin a hard time with this one
2006-12-07 10:41:53 · 4 answers · asked by wheniawoke 3 in Science & Mathematics ➔ Mathematics
(3a+5)(2a-7)
I am 100% sure this is correct - I guess and check until it works
2006-12-07 10:50:43 · answer #1 · answered by MollyMAM 6 · 1⤊ 0⤋
6a^2 - 11a - 35 = 0
6 can be broken up into 3 and 2
35 can be broken up into 7 and 5
when you cross multiply, you find that (3a-5) and (2a-7) fits the "-11a" you're looking for.
therefore, (3a-5)*(2a-7)=0
3a-5=0, a = 5/3
or
2a-7=0, a = 7/2
2006-12-07 10:47:55 · answer #2 · answered by orca1006 2 · 0⤊ 2⤋
a= -5/3 and a = 7/2. how? just use quadratic formula OR graph
2006-12-07 10:49:41 · answer #3 · answered by wbaqai 2 · 0⤊ 0⤋
What are you supposed to do with it? If they want its zeros, those are -1.6667 and 3.5.
http://www.1728.com/quadratc.htm
2006-12-07 10:44:24 · answer #4 · answered by Anonymous · 0⤊ 0⤋